Physics, asked by jiyabisht5607, 2 months ago

10 g of water at 80℃ is mixed with 50g of copper at 10℃ . Find the final temperature.

Answers

Answered by basavaraj5392

1

Answer:

Answer: ΔQ = mcΔT for water :

ΔQ₁= 80×4.2×(10-T)

∵ T - equilibrium temperature for copper :

ΔQ₂ = 50×0.4×(T-10)

Answered by priyaayika

0

Answer:

$20(t - 1) \\ hope \: its \: help \: you$

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