10
(ग) sin 52°sin 38° - cos52°cos38° का
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Answer:
sin 52°×sin (90-52)°- cos 52°×cos( 90-52)°
=sin 52°× cos 52°- cos 52°×sin 52°
=sin52°× 1/sin 52° - cos 52°×1/cos 52°
=1-1
=0
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