Question

10.
Give the correct increasing order of electrical
conductivity of aqucous solutions of following
complex entities:
Pirts), ]CIA
[Cr(NH3).]Cla
[CO(NH3), Cl]CI
IV. Ky[Płcie]
(A) III < IV< 11 <1
(C) Il<I<IV< III
(B) IV< 11 < III < 1
(D) 1< 11 <IV< III​

Answer 1

not of my level sorry

i know its guilty but

let me take time

n all i will answer your question

Answer 2

Answer:

(a) III<IV<II<I

Explanation:

Give the correct increasing order of electrical conductivity of aqueous solutions of following complex entities: I) [Pt(NH3)6]Cl4 II) [Cr(NH3)6]Cl3 III) [Co(NH3 4Cl2]Cl IV) K2[PtCl6]

Options:

III < IV < II< I

IV < II

II < I < IV < III

I < II < IV < III

Solution:

number of ions in 1st compound is= complex+4Cl= 5 in total

number of ions in 2nd compound is= complex+3Cl= 4 in total

number of ions in 3rd compound is= complex+1Cl= 2 in total

number of ions in 4th compound is= 2K+complex= 3 in total

more the number of ions, more will be the electrical conductivity

So, 1st compound has highest electrical conductivity whereas 3rd compound has lowest electrical conductivity.

Hope it helps!!! :)