Chemistry, asked by Jenny8559, 8 months ago

10 gm of non volatile solute when dissolved in 100gm of benzene raised its boiling point by 1°c what is the molar mass of the solute

Answers

Answered by nidhiakara
2

Answer:    253

Explanation:

   you need to know that

                                 change in boiling point = kb  x  molality

                                                      kb for benzene is 2.53

                                                 m = (wt/ gm mol wt) x 1000/wt of solvent

                                             so,

                                                        1 = 2.53 x ( 10/ M ) x 1000/100

                                                               M = 253

                                                              mark as brainliest mate

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