10 gm of non volatile solute when dissolved in 100gm of benzene raised its boiling point by 1°c what is the molar mass of the solute
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Answer: 253
Explanation:
you need to know that
change in boiling point = kb x molality
kb for benzene is 2.53
m = (wt/ gm mol wt) x 1000/wt of solvent
so,
1 = 2.53 x ( 10/ M ) x 1000/100
M = 253
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