Biology, asked by blaze9412, 5 months ago

10 gm of raisins were soaked overnight in pure water then they were weighed and found 13 gm mass percentage of water absorbed by raisins is​

Answers

Answered by rawat64
14

Weight of water absorbed by the raisins = (13- 10) = 3 g.

Weight of water absorbed by the raisins = (13- 10) = 3 g.The percentage of water absorbed by the raisins = \frac { 3 }{ 10 } X100=30%

Answered by mukula56789
2

Endosmosis happens when raisins are soaked in water, causing the raisins to become turgid.

The formula for calculating the proportion of water absorbed is (Final weight - Initial weight) / Initial weight * 100.

=13-10 / 10\\=3/10\\=0.3

30 is the mass percentage of water absorbed by raisins

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