10 gram Bullet moving at 200 m per second stops after penetrating 5 cm of wooden plank the magnitude of average force exerted on the bullet will be ?
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m=10×10^-3 kg
u=200m/s
s=5×10^-2m
v^2-u^2=2(a)(s)
a=4×10^5m/s^2
force exerted by bullet=mass of bullet×acc.
=4×10^3 N
u=200m/s
s=5×10^-2m
v^2-u^2=2(a)(s)
a=4×10^5m/s^2
force exerted by bullet=mass of bullet×acc.
=4×10^3 N
Kinetic Energy of Bullet
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