10 gram of an alloy of metal A and B contain 7.5 gram of metal A and the rest is meta B. Find the ratio between: (1) the weight of metal A and B in the alloy (2) the weight of metal B and the weight of the alloy
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10 g of the alloy has 7.5 g A.
Since there are only two metals in the alloy, amount of B in the alloy is 10-7.5 = 2.5 g
(1) Ratio of A to B
= 7.5:2.5
= 75:25
= 3:1
(2) Ratio of B to A+B
= 2.5:10
= 25:100
= 1:4
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Here's your answer...
10 g of the alloy has 7.5 g A.
Since there are only two metals in the alloy, amount of B in the alloy is 10-7.5 = 2.5 g
(1) Ratio of A to B
= 7.5:2.5
= 75:25
= 3:1
(2) Ratio of B to A+B
= 2.5:10
= 25:100
= 1:4
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