Question

10 gram of bullet is shot from 5kg gun with a velocity of 400m/s . what is the speed of recoil of the gun

Answer 1

According to law of conservation of linear momentum
M1(V1)=M2(V2) where M1 is the mass of the bullet,V1 is the velocity of the bullet,M2 is the mass of the gun and V2 is the recoil velocity of the gun.
10(400)=5000V2
V2=4000÷5000
V2= 0.8 m/ sec

Answer 2

Answer:

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Explanation:

after firing the velocity of bullet (v)= 400 m/s, say the velocity of gun is V

mass of bullet (m)= 10/1000 kg , mass of gun (M)= 5 kg

From momentum conservation,

0= mv + MV

V = - (m/M)*v

V = - (10\5000)*400 m/s

V = - 0.8 m/s (Negative sign indicates that velocity of gun and bullet is in opposite direction)

so the recoil velocity of the gun is 0.8 m/s