Question

10 gram of CO burns in a i r give the product which have the number of nucleons ​

Answer 1

Answer:

This is the correct answers

Answer 2

Answer:

94.7 * 10^23

Explanation:

2CO + O2 ----> 2CO2

2moles of CO  ------>  2 mol of CO2

1 mole of CO --------> 1/2 moles of CO2

10 g CO = 10/28 moles of CO

ie; 10/28 moles of CO ------> 1/2 * 10/28 moles of  CO2

= 0.18 moles of CO2

= 0.18 * 6.022 * 10^23 MOLECULES OF CO2

= 44 ( no: of protons + neutrons in 1 co2 molecule) * 2(no: moles of co2) * 0.18 * 6.022 * 10^23

= 94.7 * 10^23 nucleons

this is my answer, so pls check if its correct