Question

10 gram of hydrogen and 64 gram of oxygen were filled in a steel vessel and exploded amount of water produced in this reaction will be

Answer 1

This must be from mole concept

2moles of hydrogen combine with 1 mole of oxygen


in the question

H2 = 2 grams/mole
02= 32 grams/mole

then
5moles of H2 and 2 moles of 02 form
2moles of water
or 64 grams of water
and 6 grams of hydrogen left unused

Answer 2

Mass of hydrogen =10g

No. of moles of hydrogen =w/M= 10g/2gmol-1 =5mol

Mass of oxygen =64g

Moles of oxygen = w/M = 64g /32gmol-1 = 2mol

According to the reaction, 2H2  + O2     ------------     2 H2O

Hence, for 2 moles  of oxygen, 4 moles of hydrogen are required  and 4 moles of water is produced. Here oxygen is the limiting reagent

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