10 gram of hydrogen and 64 gram of oxygen were filled in a steel vessel and exploded amount of water produced in this reaction will be
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Answered by
1
This must be from mole concept
2moles of hydrogen combine with 1 mole of oxygen
in the question
H2 = 2 grams/mole
02= 32 grams/mole
then
5moles of H2 and 2 moles of 02 form
2moles of water
or 64 grams of water
and 6 grams of hydrogen left unused
2moles of hydrogen combine with 1 mole of oxygen
in the question
H2 = 2 grams/mole
02= 32 grams/mole
then
5moles of H2 and 2 moles of 02 form
2moles of water
or 64 grams of water
and 6 grams of hydrogen left unused
Answered by
8
Mass of hydrogen =10g
No. of moles of hydrogen =w/M= 10g/2gmol-1 =5mol
Mass of oxygen =64g
Moles of oxygen = w/M = 64g /32gmol-1 = 2mol
According to the reaction, 2H2 + O2 ------------ 2 H2O
Hence, for 2 moles of oxygen, 4 moles of hydrogen are required and 4 moles of water is produced. Here oxygen is the limiting reagent
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