10 gram of hydrogen is treated with 64 g of oxygen. The moles of water formed will be:
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This implies that 2 moles of hydrogen requires 1 mole of oxygen to obtain 2 moles of water . But v just have 64 g of O2(2 moles) that means O2 is the limiting reagent. This implies 2 moles will O2 will form 4 moles of water.
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Answer:
This implies that 2 moles of hydrogen requires 1 mole of oxygen to obtain 2 moles of water . But v just have 64 g of O2(2 moles) that means O2 is the limiting reagent. This implies 2 moles will O2 will form 4 moles of water
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