Question

10 gram of ice at 0 degree celsius is kept in a calorimeter water equivalent 10 gram how much heat should be supplied to the apparatus to operate the water is formed

Answer 1

Answer:

10

Step-by-step explanation:

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Answer 2

8200 Calories is Total Heat

Step-by-step explanation:

First 10 gms of ice will melt from 0°C ice to 0°C water,  

Heat required = 80 $\times$ 10 = 800 cal.

Now 10 gm water + calorimeter of water equivalent 10 gm is there at 0°C.  

The heat required to raise up to 100 °C  

= $(10+10)\times 1 \times (100-0)$=2000 cal.

Now for evaporation of 10 gm water heat required  

=10 $\times$ 540 cal = 5400 cal.

Total Heat required = 800+2000+5400 =8200 cal