10 gram of ice at -10°C is mixed with water at 0°C . What is the Amount of heat required to raise the temperature.
ANSWER IS 4385 JOULES
BUT I WANT THE EXPLINATION
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Answer:
here you go
Explanation:
C
v
for a monoatomic gas at constant volume is
2
3R
≈3 cal−mol
−1
K
−1
Let the atomic weight of the gas be w
∴w grams of the gas requires the 3 cal of heat to raise its temperature by 1K.
∴ 1 gram of gas will require
w
3
cal of heat to raise its temperature by 1K.
∴ 1 kg of gas will require
w
3
kcal of heat to raise its temperature by 1K.
In the question, the above quantity is given to be 0.075 kcal kg
−1
K
−1
∴
w
3
=0.075
Solving this, we get w=40
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