Question

10 gram of soda crystal (Na2CO3.10H2O) are required to neutralize 50cc of a sample of HCl solution how many CC of acid must be diluted and made upto one litre so as to produce exactly 1N HCl solution

Answer 1

Answer:

715 cc

Explanation:

The Equivalent weight of soda crystals will be equal to 143 as the molecular weight of the compound is 286 and the acidity is 2.(E=molecular weight / basicity)

Using Normality equation:

50cc of x N required 10/143 g of soda crystal

50/1000* x=10/143

Find the normality that is *(x)*

Finally

Volume*x=1000*1( in cc)

Therefore the volume required is 715 cc.