10 gram of sodium sulphate reacts with 5 gram of Barium Chloride to Form 8 gram white precipitate of Barium sulphate find out the mass of sodium chloride formed in this reaction
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16g of Nacl is formed
one volume of of barium sulphate is 8 g so two volume of sodium chloride is 16 g
one volume of of barium sulphate is 8 g so two volume of sodium chloride is 16 g
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