10 gram of water is converted into steam at atmospheric pressure and 100°c.calculate the increase in internal energy.specific latent heat of vaporization of water=540cal/gm and volume of 1 gram of water and steam are 1 cm3 and 1671 cm3
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Answer:
Work done =PΔV
=1×10
5
×1671×10
−6
J
=167.1J=39.97 cal
ΔU=Q−W
ΔU=540−40 cal
ΔU=500 cal
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