10 gram sample of a mixture of cacl2 and NACL is treated to precipitate all the calcium as calcium carbonate this calcium carbonate is heated to convert all the calcium to calcium oxide and final mass of calcium oxide as 1.68 gram the percent by mass of cacl2 in original mixture is
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hey
gd mrng
here is your answer
CaCO3 +heat--->CaO +Co2
X gms 1.68gms
100 56
[molecular mass of CaCO3=100u
molecular mass of CaO=56u]
cross multiply through the equation and solve for x grams of caco3
x=1.62x100/56
=2.89g
Cacl2 +Na2Co3 --->Caco3 +2 Nacl
x 2.89g
111 100
Again cross multiply through the equation and solve for x grams of Cacl2
x=2.89x 111/100
=3.2g
%CaCl2 in original mixture 3.2grams
Cacl2 over 10gms mixture is 32%
hope its help you
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soumya1821:
but this is not in any option (33.3, 11, 16.2, 30 percenrs are in options)
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