Question

10 grams of calcium carbonate (CaCO3) produces 3.8 grams of carbon dioxide

(CO2) and certain amount of calcium oxide (CaO). Calculate the amount of

calcium oxide formed.​

Answer 1

Answer:

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Let the amount of calcium oxide formed be x g

According to law of conservation of mass,

Mass of reactants = Mass of products

Therefore, 10 gram of CaCO3 = 3.8 grams of CO2 + x grams of CaO

x grams of CaO = 10 grams of CaCO3 – 3.8 grams of CO2

x grams of CaO = 6.2  

Answer 2

Answer:

6.2g

Explanation:

1. 10 grams of calcium carbonate (CaCO3),I.e, reactant, produces 3.8 grams of carbon dioxide (CO2) and certain amount of calcium oxide (CaO). CO2 and CaO are the products.

By law of conservation of mass

Mass of reactants = Mass of products

=>Mass of calcium carbonate (CaCO3) =

Mass of carbon dioxide (CO2) + Mass of calcium oxide (CaO)

=>10g = 3.8g + Mass of calcium oxide (CaO)

=>Mass of calcium oxide (CaO) = 6.2g