10 grams of calcium carbonate
(CaCO3) produces 3.8 grams of
carbon dioxide (CO2) and 6.2 grams
of calcium oxide (Cao). Represent
this reaction in terms of law of
conservation of mass.
Pls ans with steps
Answers
Answered by
15
Explanation:
According to the law of conversation of mass,
mass of reactant=mass of products
therefore,
10g(CaCO3)=3.8g(CO2)+6.2g(CaO)
10g(CaCO3)=(3.8g+6.2g)×(CO2+CaO)
10gCaCO3=10gCaCO3
Answered by
3
Answer:
ELet the amount of calcium oxide formed be x g
According to law of conservation of mass,
Mass of reactants = Mass of products
Therefore, 10 gram of CaCO3 = 3.8 grams of CO2 + x grams of CaO
x grams of CaO = 10 grams of CaCO3 – 3.8 grams of CO2
x grams of CaO = 6.2
xplanation:
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