Question

10 grams of ornament gold contains 6% silver if we want to reduce it to 2.5%, how much shou
pure gold to be m​

Answer 1

Given :- 10 grams of ornament gold contains 6% silver. if we want to reduce it to 2.5%, how much pure gold should be added ?

Solution :-

→ Silver in 10 gm = 6% of 10gm = (6 * 10)/100 = 0.6gm .

Now Let us assume that, x gm of pure gold is added .

then,

→ Total mixture = (10 + x) grams .

→ silver = 0.6 gm = 2.5% of mixture .

A/q,

→ 2.5% of (10 + x) = 0.6gm

→ 2.5 * (10 + x)/100 = 0.6

→ 2.5(10 + x) = 60

→ 25 + 2.5x = 60

→ 2.5x = 60 - 25

→ 2.5x = 35

→ x = 35/2.5

→ x = 14 gm. (Ans.)

Hence, 14 grams of Pure gold must be added to reduce the % of silver to 2.5 % .

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