10 grams of so2 and 10 grams of o2 are added to form so3, what will be the amount of so3
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2SO2+O2=2SO3. here,o 2 acts as a limiting reagent,so the product depends on amount of O2. 32g of o2_160g of so3 is formed. 10g of o2-? =10*160/32=50.
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