10 grams of sodium carbonate is present in 120 grams of its aqueous sol mass is what
Answers
Answered by
8
mass of sodium carbonate(solute) in the solution = 10 gram
mass of aqueous sol mass =120 gram
mass of solvent=120-10
=110 gram
Answered by
1
Answer:
Explanation:Mass of solute, w=5g
Mass of solution,w+W=10+120=130g
Mass percentage, w%=(w/w+W)*100
w%=(5/130)*100=7.6923076923
Similar questions