Question

10. নীচের সংখ্যামালাকে দুটি বর্গের অন্তররূপে প্রকাশ করি :
| (i) 391x409 (ii) (4x + 3y)(2x -3y) (iii) x​

Answer 1

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Answer 2

Answer:

1.        $400^{2} -18^{2}$

2.       $(3x)^{2} -(x+3y)^{2}$

3.       $(\frac{x+1}{2} )^{2} - (\frac{x-1}{2} )^{2}$

Step-by-step explanation:

Let a and b be two number.

Then we know, $a.b =( \frac{(a+b)}{2} )^{2} -( \frac{a-b}{2} )^{2}$

1.

Let, a = 409      b= 391    

Therefore, 409x391 =$400^{2} -18^{2}$

2.

Let a= (4x+3y)     and    b = (2x-3y)

Therefore,  (4x+3y)(2x-3y)= $(3x)^{2} - (x+3y )^{2}$

3.

Let, a= x  and  b=1

Therefore, x= $(\frac{x+1}{2} )^{2} -( \frac{x-1}{2} )^{2}$