Math, asked by ananyaag, 10 months ago

10. i dimension of a rectangular ground is 42 m x 66 m. Out side the ground,
around it, a cemented path of width 2 m is made. If 1 bag of cement is
required for 4 m path. Find how many bags of cement will be needed to
construct the path? If 4 rounds of barbed wire is used to fence the ground
(not the road) what will be the cost of wire if 1 m. barbed wire is costing
Rs. 50.​

Answers

Answered by pandiyanj
2

Answer:

5 bags of cement would be required to cover the path.

Step-by-step explanation:

Area of path = length * width

Area of path = 12m * 2.5m

Area of path = 30 m^2

One bag of cement can cover 6 m^2

30/6 = 5

5 bags of cement would be required

to cover the path.

Hope this helps.

:-)

Answered by ItZzMissKhushi
0

Answer:

Area of path = length * width

Area of path = 12m * 2.5m

Area of path = 30 m^2

One bag of cement can cover 6 m^2

30/6 = 5

5 bags of cement would be required

to cover the path.

Step-by-step explanation:

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