Question

10. (i) sin2A cosa'B + cos2 A sin2 B + cos2 A cos2 B + sin2A sin2 B = 1​

Answer 1

Answer:

LHS=(sinAcosB)

2

−(cosAsinB)

2

=(sinAcosB+cosAsinB)(sinAcosB−cosAsinB)

=sin(A+B)sin(A−B)

=sin

2

A−sin

2

B

=RHS

Hence proved

Step-by-step explanation:

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