10. If a and B are zeroes of a quadratic polynomial P(x) = 4x2-5x-1. Find the value of a²?B+aß²
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α and β are zero of the polynomial:
p(x)=4x2-5x-1
a=4,b=-5,c=-1
So, Sum of the zeroes = α + β=-\(\frac ba\) \(= \frac{5}{4}\)
Product of the zeroes = αβ=\(\frac ca\) \(= \frac{{ - 1}}{4}\)
Now, α2β + αβ2 = αβ(α + β)
\(= \frac{5}{4}\left( {\frac{{ - 1}}{4}} \right)\)
\(= \frac{{ - 5}}{{16}}\).
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