Question

10. If a, B are the zeroes of the polynomial x? - 16, then ab(a + b) is
(a) 0
(b) 4
(c) 4
(d) 16​

Answer 1

★ Let :

◼ According to the general form of Quadratic Polynomial is : “ ax² + bx + c = 0 ”.

◼ Consider the given polynomial.

a = 1

b = 0

c = - 16

★ Now :

➡ Sum of the zeroes : α + β = -b/a = -0/1 = 0

➡ Product of the zeroes : αβ = c/a = -16/1 = - 16

Now,we can find out the value of αβ(α+ β) .

➠ 0(-16)

➠ 0

∴ Value of αβ(α+ β) = 0