Question

10. if a man walks to his office at 3/4th of his usual rate he reaches office 1/3rd of an hour later than usual. how much time does he usually take to reach his office ?

Answer 1

Hey there!!

Let D be the distance, S be his usual speed.

We have D ÷ ( 3S ÷ 4 ) = D÷S + 20.

So, ( 4 ÷ 3 ) × ( D ÷ S ) = ( D ÷ S ) + 20,

Or ( 1 ÷ 3 ) × ( D ÷ S ) = 20,

we get ( D ÷ S ) = 60 (min)

Note : Formula used = Speed = Distance ÷ Time

Note : Taken 20 minutes because ( 1 ÷ 3 ) of hour = 20 minutes

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