Question

10. If cos A = 4/5, then tan A = ? * 1 point (A) 3/5 (B) 3/4 (C) 4/3 (D) 4/5

Answer 1

Answer:

C) 4/3 .

cosA = ⅘

=> sinA =

$\sqrt{1 - {( \frac{4}{5}) }^{2} }$

$= \sqrt{1 - \frac{16}{25} }$

$= \sqrt{ \frac{25 - 16}{25} }$

$= \sqrt{ \frac{9}{25} }$

= ⅗

so,

tanA = sinA/cosA

$= \frac{ \frac{4}{5} }{ \frac{3}{5} }$

= ⅘ × ⁵/3

= 4/3

this isbtje correct answer.