(10) If each side of an equilateral triangle
increases at the rate of √2 cm/ sec, find the
rate of increase of its area when its side of
length 3 cm
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1
Answer:
Let x be the side of an equilateral triangle and A be the area.
∴A=
4
3
x
2
On differentiating both sides with respect to t, we get
dt
dA
=
4
3
2x
dt
dx
Given, x=10cm
and
dt
dx
=2cm/s
∴
dt
dA
=
4
3
2×(10)×2
=10
3
cm
2
/s
Step-by-step explanation:
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