10. If F° Fe2+/Fe = 0.441 V and EºFe2+/Fe2+ = 0.771 V, the standard EMF of the reaction, Fe + 2Fe3+ 3Fe2+ will be
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Answer:
Fe+2Fe3+→3Fe2+
Anode reaction is Fe→Fe2++2e−
Cathode reaction is 2Fe3++2e−→2Fe2+
E∘Cell =E∘Cathode −E∘Anode (Eo is reduction potential )
=0.771−(−0.441)
E∘Cell =1.212V
Explanation:
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