Question

10. If n(A-B) = 10, n(B-A)= 23 n(AUB) = 50, then n (ANB) is​

Answer 1

Step-by-step explanation:

I think this is helpful ✌️

Answer 2

The n(A∩B) intersection when n(A-B) = 10, n(B-A)= 23 n(AUB) = 50 is 17 when we know the formula n(A-B) + n(B-A)= n(AUB) - n(A∪B).

Given that,

We have to find the n(A∩B) when n(A-B) = 10, n(B-A)= 23 n(AUB) = 50.

We know that,

The formula is

n(A-B) + n(B-A)= n(AUB) - n(A∪B)    (Union and intersection is subtracted the we get the resultant of A-B and B_A)

10+23=50-n(A∪B)

33 = 50-n(A∪B)

-n(A∪B) = 33-50

-n(A∪B) = -17

n(A∪B) = 17

Therefore, The n(A∩B) intersection when n(A-B) = 10, n(B-A)= 23 n(AUB) = 50 is 17 when we know the formula n(A-B) + n(B-A)= n(AUB) - n(A∪B).

To learn more about intersection visit:

https://brainly.in/question/54179002

https://brainly.in/question/15253060

#SPJ3