Question

10. If sin 0 =root 3/2
find the value of (cosec 0 + cot 0).​

Answer 1

Answer:

Step-by-step explanation:

Sin theta =√3/2

Si,

Theta = 60

We have to find

cosec theta +cot theta,

Cosec 60 = 2/√3

Cot 60 = 1/√3

So,

cosec theta +cot theta = 2/√3 +1/√3

=3/√3

= √3

Answer 2

Step-by-step explanation:

let theta be 'a'

sin(a)= √3/2

sin(a)=sin(60°)

a=60°

=>> cosec(a) +cot(a)

=>> cosec(60°) +cot(60°)

=>> 2/√3+1/√3

=>> 1+2/✓3

=>> 3/√3

=>> √3×√3/√3

=>> √3