10. If tan 20=cot (0 +6), where 20 and (+6°) an acute angles, find the
value of 0.
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Answer:
tan2A=cot(A+6)
cot(90-2A)=cot(A+6)
90-2A=A+6
90-6=A+2A
84=3A
A=84/3=28
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