(10) If tanA=a, tan2B=b and tanA+ tan2B= tan3A then
(A) a=b
(B) ab =1
(C) a+b=0
(D) b=2a
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Answer:
D) b=2a
Step-by-step explanation:
TANA=a
TAN2B=b
TANA+TAN2B=TAN3A
SO
A+B=3A
A=B
PUTTING THIS VALUE IN QUESTION
TANA=a
TAN2A=b
TANA=b/2
Comparing both sides
a=b/2
b=2a
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