Question

10. If the diagonal of a rectangle is 10 cm and its width
is 6 cm, find its area.​

Answer 1

Answer:

area of rectangle =

Step-by-step explanation:

area of rectangle =length ×breadth

ATQ

length =? ,breadth =6,diagonal=10

(diagonal )^2=(length)^2+(breadth) ^2

(10)^2=(length)^2+(6)^2

100 =(length) ^2+36

(length) ^2=100-36=64

length=√64

length =8

area=length×breadth

area of rectangle =8×6=48cm^2

Answer 2

Answer:

48 cm²

Step-by-step explanation:

Bredth = 6cm

let the length be "B"

Acc. to pythagoras theorem :

H²= B²+P²

10²=B²+6²

√100-36 = B

√64= B

8= B

Now, Area of triangle is LB

8×6= 48cm²