Question

10.If the length and breadth of a rectangle are 15cm and 10cm, respectively, then its area is: *
A. 100 sq.cm
B. 150 sq.cm
C. 115 sq.cm
D. 200 sq.cm​

Answer 1

Answer:

150 sq.cm

Step-by-step explanation:

length of rectangle = 15cm

breadth of rectangle = 10 cm

Area of rectangle = l × b = 15 cm × 10 cm = 150 cm

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Answer 2

Given: The length and breadth of a rectangle are 15cm and 10cm respectively.

Need To Find : Area of Rectangle.

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❍ Finding Area of Rectangle using the Formula is given by :

$\underline {\frak{As\:We\:Know\:that\::}}$

⠀⠀⠀⠀⠀ $\underline {\boxed {\sf{ Area _{(Rectangle)} = l\times b\:or\:lb\: \:sq.units .}}}$

⠀⠀⠀⠀⠀ Here l is the Length of Rectangle in cm and b is the Breadth of Rectangle in cm .

⠀⠀⠀⠀$\underline {\bf{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

⠀⠀⠀⠀⠀ $:\implies \sf{ Area _{(Rectangle)} =10 \times 15 .}$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  Area_{(Rectangle)} = 150\: cm^{2}}}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm { Area \:of\:Rectangle \:is\:150\: cm^{2}}}}$

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More To Know :

$\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}$

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