Physics, asked by chengalakumari19902, 11 months ago

10
If the Pb2+ concentration is maintained at1.OM
what is the [Cu2+], when the cell potential
drops to zero ? Eºcell = 0.473V.
Pb/Pb2+// Cu2+/ Cus)​

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Answered by Anonymous
0

Answer:

2 Al0(s) + 3 Cl20(g) --> 2 Al+3Cl3-1(s) ... 2. Using standard reduction potentials, calculate the potential for the following cell at 298 K: ... Thus, the overall reaction is: Zn(s) + Cu2+(aq) --> Zn2+ ...

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Answered by Anonymous
1

Answer:

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