10. If the perimeter of the rhombus is 40 cm and one of its diagonal is 16 cm,
then find its area.
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Answer:
Side of Rhombu=40/4=10cm
the other diagonal=2V10^2-8^2
=2 v36=2x6=12 Cm.
Area = d1xd2/2=I6x12/2=96cm2
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