Question

10. If the sum of three consecutive positive integers is 48 then the smallest integer is
a. 16.
b. 24.
c. 15.
d. 17.
​

Answer 1

Answer: c.15

Step-by-step explanation: it means x+x+1+x+2=48

So 3x = 45

   x = 15

Answer 2

Answer:

c. 15.

The smallest integer is 15

Step-by-step explanation:

Given:

• The sum of three consecutive positive integers is 48

To find:

•The smallest integer

Solution :

Let,

Three consecutive positive integers :

First number = x

Second number = x + 1

Third number = x + 2

According to question :

the sum of three consecutive positive integers is 48

So,

➨ x + x + 1 + x + 2 = 48

➨ 3x + 3 = 48

➨ 3x = 48 - 3

➨ 3x = 45

➨ x = 45 / 3

➨ x = 15

Second number = x + 1

➨ 15 + 1

➨ 16

Third number = x + 2

➨ 15 + 2

➨ 17

Therefore,

c. 15

The smallest integer is 15