Question

10. If x = √3 + √2 , find (a) x + 1 x (b) x2 + 1 x2 (c) x2 - 1 x2 ) d ) ( x + 1 x ) 3

Answer 1

Answer:

a) 2 root 3+2root 2 B) 2(root 3+ROOT 2+1) C)  2(root 3+root 2-1) D) 6( ROT 3+ ROOT 2)

Answer 2

Answer:

x = √3 + √2

a) x + 1x

= √3 + √2 + 1(√3 + √2)

= √3 + √2 + √3 + √2

= 6.252

b) x2 + 1x2

= (√3 +√2)2 + 1(√3 + √2)2

= 2√3 + 2√2 + 2√3 + 2√2

= 12.585

c) x2 - 1x2

= (√3 +√2)2 - 1(√3 + √2)2

= 2√3 + 2√2 - 2√3 + 2√2

= 5.656

d) (x + 1x) 3

= (√3 + √2 + 1(√3 + √2))3

= (√3 + √2 + √3 + √2 )3

= 3√3 + 3√2 + 3√3 + 3√2

= 18.877

Plzzz mark me brainiest!