Question

10. If (y - 3) is a factor of y? - 2y2 - 9y+18 then find the other two factors.​

Answer 1

y2 - 2y2 - 9y+18

= y2 - 3y2 + y2 - 3y - 6y +18

= y2(y-3)+y(y-3)-6(y-3)

= (y-3)(y2+y-6)

=(y-3)(y2+3y-2y-6)

= (y-3)[y(y+3)-2(y+3)]

=(y-3)(y+3)(y-2)

so, other factors are y+3 and y-2

Answer 2

Answer:

y2-2y2-9y+18

=y2-3y2+y2-3y-6y+18

=y2(y-3) +y(y-3) -6( y-3)

=(y-3) (y2+y-6)

=(y-3) (y2+3y-2y-6)

=(y-3) [y(y+3) -2(y+3)]

=(y-3) (y+3)(y-2)

So, other factors are y+3 and y-2

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