Question

10. if y= x log x , then find dy/dx.​

Answer 1

Answer: 2xlog-1(logx )

Step-by-step explanation:

y=x^logx

logy = logx^1ogx

logy = (logx) (logx)

1/y dy/dx  = (2logx)(1/x)

dy/dx = (2log) x^logx/x

=2xlog-1(logx)

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