Math, asked by something143143, 11 months ago

10. In a class of 60, where number of girls are twice that of boys,
Kamal ranked 17th from the top. If there are 9 girls before
Kamal, how many boys after him in rank?​

Answers

Answered by happug
2

Answer:

31

Step-by-step explanation:

number of boys = 20 and numbers of girls = 40. Number of students behind Kamal in rank = (60 - 17) = 43. Number of girls ahead of Kamal in rank = 9. Number of girls behind Kamal in rank = 40 - 9 = 31.

Answered by waniyajeeyahoney
4

Let the number of boys be x.  Then, numbers of girls = 2x.

.'. x + 2x = 60  or  3x = 60  or  x = 20.

So, number of boys = 20 and numbers of girls = 40.

Number of students behind Kamal in rank = (60 - 17) = 43.

Number of girls ahead of Kamal in rank = 9.

Number of girls behind Kamal in rank = 40 - 9 = 31.

.'. Number of boys behind Kamal in rank = 43 - 31 = 12.

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