CBSE BOARD X, asked by ajjubhai87, 2 months ago

10.
In a field, dry fodder for the cattle is heaped in a conical shape. The height
of the cone is 2.1m. and diameter of base is 7.2 m. Find the volume of the
fodder if it is to be covered by polythin in rainy season then how much
minimum polythin sheet is needed?
【[π=22/7] and √17.37 = 4.17}】​

Answers

Answered by shaniasingh
1

Answer:

The volume of a cone is 28.49 m³ .

Step-by-step explanation:

Formula

Volume\ of\ a\ cone = \pi r^{2} \frac{h}{3}Volume of a cone=πr 2 3h

Where r is the radius and h is the height .

As given

In a field,dry fodder for the cattel is heaped in a conical shape.

The height of cone is 2.1 m,and diameter of base is 7.2m.

Radius = \frac{Diameter}{2}Radius=

2

Diameter

Radius = \frac{7.2}{2}Radius=

2

7.2

Radius = 3.6 m

Height = 2.1 m

\pi = 3.14π=3.14

Putting all the values in the formula

Volume\ of\ a\ cone =3.14\times 3.6\times 3.6\times \frac{2.1}{3}Volume of a cone=3.14×3.6×3.6×

3

2.1

Volume\ of\ a\ cone =\frac{2.1\times 3.14\times 3.6\times 3.6}{3}Volume of a cone=

3

2.1×3.14×3.6×3.6

Volume\ of\ a\ cone =\frac{85.46\ (Approx)}{3}Volume of a cone=

3

85.46 (Approx)

Volume of a cone = 28.49 m³ (Approx)

Therefore the volume of a cone is 28.49 m

hope this helps~

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