Question

10. In a parallelogram ABCD find the measure of all the angles if one its angles is 15° less than twice the smallest angle.

Answer 1

Answer:

65°,115°,65° and 115°

Step-by-step explanation:

Let the smallest angle be x

therefore, one angle =2x-15

(2x-15)+(x)=180°{sum of adjacent sides of ||gm=180°}

3x=195°

x=65°

one angle=65°

another angle=180-65=115°

third angle=65° {opposite sides of ||gm os equal}

fourth angle =115°

Hope this helps you!!