Question

10. In A PQR, DE || QR; if PD = 2cm, PQ = 8cm, PE = 3 cm, then PR=

11. In a triangle XYZ, if the internal bisector of ZX meets YZ in P, then
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Answer 1

Given :-

• DE || QR .
• PD = 2 cm.
• PQ = 8 cm.
• PE = 3 cm.

To Find :-

• PR = ?

Solution :-

we know that,

• If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in the same ratio. { Also called BPT(Basic Proportionality Theorem) } .

since DE || QR .

so,

→ PD/PQ = PE/PR (By BPT)

putting values we get,

→ (2/8) = (3/PR)

→ (1/4) = (3/PR)

→ PR = 4 * 3

→ PR = 12 cm (Ans.)

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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