Question

10. In A PQR. right-angled at Q. PR + QR = 25 cm and PQ=5 cm. Determine the values of
sin P, cos P and tan P.​

Answer 1

Answer:

Let PR be 'x' and QR be = 25-X

Using Pythagoras Theorem,

==>PR^2 = PQ^2 + QR^2

x^2 = (5)^2 + (25-x)^2

X^2 = 25 + 625 + x^2 - 50x

50x

= 650

x = 13

therefore, PR = 13 cm

and,

Now, Sin P = opposite/hypotenuse = QR/PR = 12/13

QR = (25 - 13) = 12 cm

Tan P= opposite/adjacent

= = QR/PQ = 12/5

Cos P= adjacent/hypotenuse = PQ/PR = 5/13

Answer 2

Answer:

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