Math, asked by anjireddy4453, 9 months ago


10. In a quadrilateral ABCD, side AD = 15 cm, DC = 13 cm, CB = 14 cm and AB = 12 cm, the
diagonal AC = 16 cm. Find its area

Answers

Answered by muskr620038
0

Step-by-step explanation:

✓15+0+3+2=3✓10

✓19+7+7+5=7✓95

add both

sorry if it is wrong then

Answered by adityatravelskorba
2

Answer:

Consider ΔABD :

s = (13 + 5 + 12)/2 cm

s = 15 cm

By heron formula, Area of ΔABC

=

15×(15−13)×(15−5)×(15−12)

cm²

= 30 cm²

Consider ΔBCD :

s = (16 + 20 + 12)/2 cm

s = 24 cm

By heron formula, Area of ΔBCD

=

24×(24−16)×(24−20)×(24−12)

cm²

= 96 cm²

Area of quadrilateral ABCD

= Area of ΔABC + Area of ΔBCD

= (30 + 96) cm²

= 126 cm²

Step-by-step explanation:

hope this helps u

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