Question

10. In a right angled triangle ABC, AB=12cm, BC=8cm. Find AC​

Answer 1

Answer:

In the given figure, let CE=CF=x

It is also given that AB=12 cm, BC=8 cm and AC=10 cm, therefore,

AF=AD=10−x

BE=BD=8−x

Now consider,

AB=AD+BD

⇒12=10−x+8−x

⇒12=18−2x

⇒2x=18−12

⇒2x=6

⇒x=

2

6

=3

Therefore, CE=x=3 cm, AF=10−3=7 cm and BD=8−3=5 cm

Hence, CE=3 cm, AF=7 cm and BD=5 cm.